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Fix AudioOutput example when no audio devices are available.

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Don't try to generate audio data with an invalid QAudioFormat, which
can happen when no audio devices are available.

Change-Id: I4de82dbf64def55fee21cf63ef99888a8084bd95
Reviewed-by: Christian Stromme <christian.stromme@digia.com>
This commit is contained in:
Yoann Lopes
2014-06-12 18:57:54 +02:00
parent a63da4b593
commit 382d4c873a
1 changed files with 9 additions and 6 deletions
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15
examples/multimedia/audiooutput/audiooutput.cpp
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@@ -66,7 +66,8 @@ Generator::Generator(const QAudioFormat &format,
: QIODevice(parent)
, m_pos(0)
{
generateData(format, durationUs, sampleRate);
if (format.isValid())
generateData(format, durationUs, sampleRate);
}
Generator::~Generator()
@@ -133,11 +134,13 @@ void Generator::generateData(const QAudioFormat &format, qint64 durationUs, int
qint64 Generator::readData(char *data, qint64 len)
{
qint64 total = 0;
while (len - total > 0) {
const qint64 chunk = qMin((m_buffer.size() - m_pos), len - total);
memcpy(data + total, m_buffer.constData() + m_pos, chunk);
m_pos = (m_pos + chunk) % m_buffer.size();
total += chunk;
if (!m_buffer.isEmpty()) {
while (len - total > 0) {
const qint64 chunk = qMin((m_buffer.size() - m_pos), len - total);
memcpy(data + total, m_buffer.constData() + m_pos, chunk);
m_pos = (m_pos + chunk) % m_buffer.size();
total += chunk;
}
}
return total;
}